Cars Q&A
Dear Sir,
I have got 2 engines as under:
1. Maximum power : 118 ps @ 6600 rpm
Torque : 146 Nm @ 4800 rpm
2. Maximum power : 68 ps @ 4000 rpm
Torque : 16.3kgm @ 2000 rpm
Please let me know as to how to read these enteries and as to which is a better engine and why ?
Regards,
Irfan Bandukwala
By IRFAN BANDUKWALA 06 June 2010
Answer:
Expert`s comment:
Hi,
Considering conversion factor of 1 NM = 1Kg-M*9.80, 16.3 Kg-M equals app 160 NM.
First engine power delivers power of 118@6600 rpm and second delivers 68PS@4000 RPM.Also torque developed in second is higher and at much lesser RPM .
To select one, First engine has better combination of higher power and considerble torque and hence makes better selection.
Answer by Shiva Shankar 06 June 2010
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