City
Please Tell Us Your City

Cars Q&A

Question
Dear Sir, I have got 2 engines as under: 1. Maximum power : 118 ps @ 6600 rpm Torque : 146 Nm @ 4800 rpm 2. Maximum power : 68 ps @ 4000 rpm Torque : 16.3kgm @ 2000 rpm Please let me know as to how to read these enteries and as to which is a better engine and why ? Regards, Irfan Bandukwala
By IRFAN BANDUKWALA 06 June 2010
Answer:
expert
Expert`s comment:

Hi,
Considering conversion factor of 1 NM = 1Kg-M*9.80, 16.3 Kg-M equals app 160 NM.

First engine power delivers power of 118@6600 rpm and second delivers 68PS@4000 RPM.Also torque developed in second is higher and at much lesser RPM .

To select one, First engine has better combination of higher power and considerble torque and hence makes better selection.

Answer by Shiva Shankar 06 June 2010
Post your answer:
Your answer

Provide Contact Details